Undergraduate → Calculus → Integral Calculus ↓
Improper Integrals
In calculus, integration is a fundamental concept that helps us find areas under curves, among many other applications. This concept gets a little more complicated when we move into the realm of improper integrals. An improper integral is an integral that arises when the function we want to integrate is unbounded or when the limits of integration are infinite, which are situations that do not fit the typical setup of a definite integral.
Broadly speaking, improper integrals help us extend the ideas of definite integrals to a wider class of functions and intervals that includes infinity. They are an essential topic in undergraduate mathematics, as they involve integrals that are frequently encountered when dealing with real-world problems.
Types of improper integrals
There are two primary types of improper integrals:
- Improper integrals with infinite limits
- Improper integrals with unbounded integrals
1. Improper integrals with infinite limits
The first type occurs when one or both of the limits of integration are -∞
or ∞
. Let's consider the integral:
∫ a ∞ f(x) dx
Here, the upper limit of integration is infinity. We need to evaluate it as a limit. We rewrite it as:
lim b→∞ ∫ a b f(x) dx
If this limit exists and is finite, we say that the improper integral converges. If it does not converge, we say that it diverges.
Let us consider a simple example:
∫ 1 ∞ (1/x 2 ) dx
Rewriting this using limits, we get:
lim b→∞ ∫ 1 b (1/x 2 ) dx
Finding the integral, we get:
= lim b→∞ [-1/x] 1 b
= lim b→∞ [-1/b + 1/1]
= lim b→∞ (1 - 1/b)
= 1
Hence this integral converges to 1.
2. Improper integrals with unbounded integrals
The second type of improper integral arises when the integrand has an infinite discontinuity within the interval [a, b] or at its boundaries. For example:
∫ 0 1 (1/√x) dx
Here, the integral becomes infinite as x approaches zero. We have to write the integral as follows:
lim t→0⁺ ∫ t 1 (1/√x) dx
Let us evaluate it step by step:
= lim t→0⁺ [2√x] t 1
= lim t→0⁺ [2√1 - 2√t]
= 2 - 0
= 2
In this case the integral converges to 2.
Visual example
To better understand these ideas, let's use some visual examples.
Imagine that we are integrating the function f(x) = 1/x 2
over the interval [1, ∞]. This function looks like this:
This graph shows that as x approaches infinity, the value of the function decreases and approaches the x-axis, which indicates convergence in this context.
Now, consider f(x) = 1/√x
on the interval [0, 1]. The function looks like this:
This shows that the function rises to infinity as it approaches zero, but falls back towards 1 as it moves to the right.
Testing the convergence of improper integrals
It is important to determine the convergence or divergence of improper integrals. There are several methods for testing convergence:
1. Comparison test
In the comparison test the improper integral is compared with another integral whose convergence is already known. The basic idea is this:
- If
0 ≤ f(x) ≤ g(x)
for all x in the interval, and if∫ g(x) dx
is convergent, then∫ f(x) dx
is also convergent. - If
f(x) ≥ g(x) ≥ 0
for all x, and if∫ g(x) dx
diverges, then∫ f(x) dx
also diverges.
Example: Show that ∫ 1 ∞ (1/(x²+1)) dx
converges.
Compare this with ∫ 1 ∞ (1/x²) dx
, which we know is convergent. Clearly, 0 ≤ 1/(x²+1) ≤ 1/x²
Thus, by the comparison test, ∫ 1 ∞ (1/(x²+1)) dx
is also convergent.
2. Limit comparison test
The limit comparison test is an extension of the comparison test, where we assume that f(x) > 0
and g(x) > 0
.
define:
lim x→∞ [f(x)/g(x)] = l
If L
is a positive finite number, then ∫ f(x) dx
and ∫ g(x) dx
will both either converge or diverge.
Example: Consider ∫ 1 ∞ (3/(2x²+5x+3)) dx
.
Let g(x) = 1/x²
. Now calculate:
L = lim x→∞ [(3/(2x²+5x+3))/(1/x²)]
Simplification:
= lim x→∞ [3x²/(2x²+5x+3)]
= lim x→∞ [3/(2+(5/x)+(3/x²))]
= 3/2
Since L
is a positive finite number, both integrals converge simultaneously. Therefore, ∫ 1 ∞ (3/(2x²+5x+3)) dx
converges.
Applications and significance
Improper integrals are found everywhere in mathematics and science. They are important in probability theory, especially in determining distributions with infinite support. They also occur in physics when evaluating the total work done by a force when the distance is infinite.
In addition, many results and techniques in calculus, such as the residue theorem in complex analysis, beautiful proofs in geometry, and the solutions of differential equations, also use improper integrals.
Conclusion
Understanding improper integrals is an integral part of a strong knowledge of calculus. Their convergence or divergence determines whether certain regions, probabilities, and physical quantities can be effectively calculated. Mastering this topic requires being comfortable with limits and familiar with various tests for convergence, which paves the way for deeper mathematical insights.
It's important to work through a number of examples, both analytically and graphically, to solidify these concepts and develop an intuitive understanding that you can apply in advanced mathematical contexts.