Grade 10 → Algebra → Arithmetic Progressions ↓
Definition of Arithmetic Progression
An Arithmetic Progression (AP) is a sequence of numbers in which the difference between any two successive numbers (terms) is constant. This fixed difference is known as the "common difference". Understanding it allows us to explore various properties and characteristics of this type of sequence in mathematics.
Understanding the terms
Let's break down the components of an arithmetic progression. First, we have:
- First term (a): It is the starting number from which the sequence starts.
- Common Difference (d): It is the difference that is added to each term to reach the next term in the sequence.
- n-th term (Tn): The n-th term of an arithmetic sequence can be found using the following formula:
tn = a + (n - 1) * d
Example of arithmetic progression
To understand Arithmetic Progression better, let us consider a simple example:
Imagine we have this sequence: 3, 6, 9, 12, 15,...
- Here, the first term is (a)
3
. - The common difference (d) is
3
, since each number is 3 units more than the previous number (6 - 3 = 3, 9 - 6 = 3, and so on).
Thus, the sequence can be defined as:
tn = 3 + (n - 1) * 3
Now, if we want to find the 5th term in the sequence, we substitute 5 for n:
T5 = 3 + (5 - 1) * 3 = 3 + 4 * 3 = 3 + 12 = 15
Therefore, the 5th term is 15, which confirms the sequence we wrote at the beginning.
Visual understanding
To visualize this, consider the following:
These lines represent the common spacing between numbers, helping us to see the uniform growth of the sequence.
More examples
Let's look at some additional examples to deepen our understanding:
Example 1
Consider the sequence: 10, 15, 20, 25, ...
- The first term,
a
, is10
. - Each term increases by
5
, sod
is5
.
So, the formula for the nth term is:
TN = 10 + (N - 1) * 5
If we want to find the 7th term:
T7 = 10 + (7 - 1) * 5 = 10 + 30 = 40
Thus, the 7th term is 40.
Example 2
What if the sequence is decreasing, like: 20, 17, 14, 11, ...?
- Here, the first term is
a
20
. - The terms decrease by
3
, sod
is-3
.
The formula for the n-th term is:
TN = 20 + (N - 1) * (-3)
Let us find the fourth term:
T4 = 20 + (4 - 1) * (-3) = 20 - 9 = 11
So, as expected, the fourth term is 11.
Sum of an arithmetic progression
The sum of all the terms in an arithmetic progression can also be easily calculated. This summation is especially useful when you want to add a large number of terms without having to do it manually.
The formula for finding the sum of the first n terms (Sn) is:
Sn = n/2 * (2a + (n - 1) * d)
Let's take a sequence and find its sum:
Consider the sequence: 5, 10, 15, ..., where we want to find the sum of the first 6 terms.
Use the given formula:
a = 5 d = 5 N = 6 SN = 6/2 * (2 * 5 + (6 - 1) * 5) = 3 * (10 + 25) = 3 * 35 = 105
Therefore, the sum of the first 6 terms is 105.
Arithmetic progression in real life
Arithmetic progressions are not just theoretical constructs; they often occur in real life. Any situation where the rate of increase or decrease is constant can be modeled using an arithmetic progression.
A great example of this is savings growth. If a person saves a certain amount every month, the total savings form an arithmetic sequence, with the monthly sum being the common difference.
Conclusion
Arithmetic progressions serve as fundamental concepts in algebra and form the basis of more sophisticated applications in both mathematics and its real-world applications. By mastering this concept, we gain insight into various natural and financial progressions that span across many fields of study.
The ease with which arithmetic progressions can be calculated makes them a powerful tool for both students and mathematicians, encouraging further exploration of mathematical sequences and categories.